{"lastrdtime":1515998187379,"creditbalance":"$5.00","contactmode":"0100000003","consname":"100000030060","consno":"100000030060","consaddr":"北京市海淀区中关村","lastreading":"125.00"}

现在有上面JSON格式的字符串, 如何获取consno对应的值100000030060?

==方式一:Google的Gson.================================================

1.基于maven,导入谷歌的Gson包:

     
         
      
       com.google.code.gson
          
      
       gson
          
      
       2.8.2
      
     

2.创建Gson对象, 将JSON字符串转为Map对象, Map取值就哦了.(转成自定义的javaBean, 通过getXxx()取值也可以)

Gson gson = new Gson();Map map = gson.fromJson(stringEntity, Map.class); System.out.println(map.get("consno"));

结果:

100000030060

==方式二:阿里的FastJson.================================================

1.基于maven, 导入阿里的FastJson包:

     
         
      
       com.alibaba
          
      
       fastjson
          
      
       1.2.41
      
     

2.调用JSON类的parseObject方法, 将字符串转为JSONObject:

JSONObject jsonObject = JSON.parseObject(jsonEntity);System.out.println(jsonObject.get("consno"));

结果:

100000030060

 

附:

package com.test.com.pers.others;import com.alibaba.fastjson.JSON;import com.alibaba.fastjson.JSONObject;import com.google.gson.Gson;import java.util.Map;/** * Created by yadongliang on 2018/1/15 0015. */public class GetJsonParameter {    public static void main(String[] args) {        String stringEntity = "{'consno':'100000030060','consaddr':'北京市海淀区中关村'}";        /**         * 方式一:Google的Gson.         */        Gson gson = new Gson();        Map map = gson.fromJson(stringEntity, Map.class);        System.out.println(map.get("consno"));        System.out.println(map.get("consaddr"));        /**         * 方式二:阿里的FastJson.         */        JSONObject jsonObject = JSON.parseObject(stringEntity);        System.out.println(jsonObject.get("consno"));        System.out.println(jsonObject.get("consaddr"));        System.out.println(jsonObject.getString("consno"));        System.out.println(jsonObject.getString("consaddr"));    }}

 

另, 可参考另一篇:

这篇讲的更细致...